1
GATE EE 2010
MCQ (Single Correct Answer)
+2
-0.6
Consider a three-core, three phase, $$50$$ $$Hz$$, $$11$$ $$kV$$ cable whose conductors are denoted as $$R, Y$$ and $$B$$ in the figure. The inter-phase capacitance $$\left( {{C_1}} \right)$$ between each pair of conductors is $$0.2$$ $$\mu F$$ and the capacitance between each line conductor and the sheath is $$0.4$$ $$\mu F$$ . The per-phase charging current is GATE EE 2010 Power System Analysis - Parameters and Performance of Transmission Lines Question 32 English
A
$$2.0$$ $$A$$
B
$$2.4$$ $$A$$
C
$$2.7$$ $$A$$
D
$$3.5$$ $$A$$
2
GATE EE 2009
MCQ (Single Correct Answer)
+2
-0.6
Match the items List-$${\rm I}$$ (To) with the items in List-$${\rm II}$$ (Use) and select the correct answer using the codes given below the lists.

List-$${\rm I}$$
$$A.$$ improve power factor
$$B.$$ reduce the current ripples
$$C.$$ increase the power flow in line
$$D$$ reduce the Ferranti effect

List-$${\rm II}$$
$$1.$$ shunt reactor
$$2.$$ shunt capacitor
$$3.$$ series capacitor
$$4.$$ series reactor

A
$$a \to 2,\,\,b \to 3,\,\,c \to 4,\,\,d \to 1$$
B
$$a \to 2,\,\,b \to 4,\,\,c \to 3,\,\,d \to 1$$
C
$$a \to 4,\,\,b \to 3,\,\,c \to 1,\,\,d \to 2$$
D
$$a \to 4,\,\,b \to 1,\,\,c \to 3,\,\,d \to 2$$
3
GATE EE 2008
MCQ (Single Correct Answer)
+2
-0.6
A lossless transmission line having Surge Impedance Loading $$(SIL)$$ of $$2280$$ $$MW.$$ A Series capacitive compensation of $$30$$% is emplaced. Then $$SIL$$ of the compensated transmission line will be
A
$$1835$$ $$MW$$
B
$$2280$$ $$MW$$
C
$$2725$$ $$MW$$
D
$$3257$$ $$MW$$
4
GATE EE 2007
MCQ (Single Correct Answer)
+2
-0.6
Single line diagram of a $$4$$-bus single source distribution system is shown below. Branches $${e_1},\,\,$$ $${e_2},\,\,$$ $${e_3}\,\,$$ and $${e_4}\,\,$$ have equal impedences. The load current values indicated in the figure are in per unit. GATE EE 2007 Power System Analysis - Parameters and Performance of Transmission Lines Question 7 English

Distribution Company's policy requires radial system operation with minimum loss. This can be achieved by opening of the branch

A
$${e_1}$$
B
$${e_2}$$
C
$${e_3}$$
D
$${e_4}$$
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