1
JEE Advanced 2015 Paper 1 Offline
Numerical
+4
-0
A Young's double slit interference arrangement with slits S1 and S2 is immersed in water (refractive index = 4/3) as shown in the figure. The positions of maxima on the surface of water are given by x2 = p2m2$$\lambda$$2 $$-$$ d2, where $$\lambda$$ is the wavelength of light in air (refractive index = 1). 2d is the separation between the slits and m is an integer. The value of p is
Your input ____
2
JEE Advanced 2015 Paper 1 Offline
Numerical
+4
-0
Consider a concave mirror and a convex lens (refractive index = 1.5) of focal length 10 cm each, separated by a distance of 50 cm in air (refractive index = 1) as shown in the figure. An object is placed at a distance of 15 cm from the mirror. Its erect image formed by this combination has magnification M1. When the set-up is kept in a medium of refractive index $${7 \over 6}$$, the magnification becomes M2. The magnitude $$\left| {{{{M_2}} \over {{M_1}}}} \right|$$ is
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3
JEE Advanced 2015 Paper 1 Offline
Numerical
+4
-0
An infinitely long uniform line charge distribution of charge per unit length $$\lambda$$ lies parallel to the y-axis in the y-z plane at $$z = {{\sqrt 3 } \over 2}$$a (see figure). If the magnitude of the flux of the electric field through the rectangular surface ABCD lying in the x-y plane with its centre at the origin is $${{\lambda L} \over {n{\varepsilon _0}}}$$ ($${{\varepsilon _0}}$$ = permittivity of free space), then the value of n is
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4
JEE Advanced 2015 Paper 1 Offline
Numerical
+4
-0
Consider a hydrogen atom with its electron in the nth orbital. An electromagnetic radiation of wavelength 90 nm is used to ionize the atom. If the kinetic energy of the ejected electron is 10.4 eV, then the value of n is (hc = 1242 eV nm)
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Total Questions
Chemistry
20
Mathematics
20
Physics
20
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