1
JEE Advanced 2015 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2
The figures below depict two situations in which two infinitely long static line charges of constant positive line charge density $$\lambda $$ are kept parallel to each other. In their resulting electric field, point charges $$q$$ and $$-q$$ are kept in equilibrium between them. The point charges are confined to move in the $$x$$ direction only. If they are given a small displacement about their equilibrium positions, then the correct statement(s) is (are)
JEE Advanced 2015 Paper 1 Offline Physics - Electrostatics Question 48 English
A
Both charges execute simple harmonic motion
B
Both charges will continue moving in the direction of their displacement
C
Charge $$+q$$ executes simple harmonic motion while charge $$-q$$ continues moving in the direction of its displacement
D
Charge $$-q$$ executes simple harmonic motion while charge $$+q$$ continues moving in the direction of its displacement
2
JEE Advanced 2015 Paper 1 Offline
Numerical
+4
-0
Two spherical stars A and B emit blackbody radiation. The radius of A is 400 times that of B and A emits 104 times the power emitted from B. The ratio $$\left( {{{{\lambda _A}} \over {{\lambda _B}}}} \right)$$ of their wavelengths $${{\lambda _A}}$$ and $${{\lambda _B}}$$ at which the peaks occur in their respective radiation curves is
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3
JEE Advanced 2015 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2
A container of fixed volume has a mixture of one mole of hydrogen and one mole of helium in equilibrium at temperature T. Assuming the gases are ideal, the correct statement(s) is(are)
A
The average energy per mole of the gas mixture is 2RT
B
The ratio of speed of sound in the gas mixture to that in helium gas is $$\sqrt {{6 \over 5}} $$
C
The ratio of the rms speed of helium atoms to that of hydrogen molecules is $${1 \over 2}$$
D
The ratio of the rms speed of helium atoms to that of hydrogen molecules is $${1 \over {\sqrt 2 }}$$
4
JEE Advanced 2015 Paper 1 Offline
Numerical
+4
-0
A bullet is fired vertically upwards with velocity v from the surface of a spherical planet. When it reaches its maximum height, its acceleration due to the planet’s gravity is $${\left( {{1 \over 4}} \right)^{th}}$$ of its value at the surface of the planet. If the escape velocity from the planet is $${v_{esc}} = v\sqrt N $$, then the value of N is (ignore energy loss due to atmosphere)
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