1
JEE Advanced 2013 Paper 1 Offline
Numerical
+4
-0
The coefficient of three consecutive terms of $${\left( {1 + x} \right)^{n + 5}}$$ are in the ratio $$5:10:14.$$ Then $$n$$ =
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2
JEE Advanced 2013 Paper 1 Offline
Numerical
+4
-0
Consider the set of eight vectors $$V = \left\{ {a\,\hat i + b\,\hat j + c\hat k:a,\,b,\,c\, \in \left\{ { - 1,\,1} \right\}} \right\}$$. Three non-coplanar vectors can be chosen from v in $${2^p}$$ ways. Then p is
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3
JEE Advanced 2013 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Let $${S_n} = {\sum\limits_{k = 1}^{4n} {\left( { - 1} \right)} ^{{{k\left( {k + 1} \right)} \over 2}}}{k^2}.$$ Then $${S_n}$$can take value(s)
A
1056
B
1088
C
1120
D
1332
4
JEE Advanced 2013 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
Perpendiculars are drawn from points on the line $\frac{x+2}{2}=\frac{y+1}{-1}=\frac{z}{3}$ to the plane $x+y+$ $z=3$. The foot of perpendiculars lie on the line
A
$\frac{x}{5}=\frac{y-1}{8}=\frac{z-2}{-13}$
B
$\frac{x}{2}=\frac{y-1}{3}=\frac{z-2}{-5}$
C
$\frac{x}{4}=\frac{y-1}{3}=\frac{z-2}{-7}$
D
$\frac{x}{2}=\frac{y-1}{-7}=\frac{z-2}{5}$
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