1
GATE ECE 2010
MCQ (Single Correct Answer)
+1
-0.3
For the output F to be 1 in the logic circuit shown, the input combination should be GATE ECE 2010 Digital Circuits - Logic Gates Question 23 English
A
A = 1, B= 1. C = 0
B
A = 1, B= 0,C = 0
C
A = 0, B= 1. C = 0
D
A = 0, B= 0, C = 1
2
GATE ECE 2010
MCQ (Single Correct Answer)
+1
-0.3
A transmission line has a characteristic impedance of 50 $$\Omega $$ and a resistance of 0.1 $$\Omega $$/m. If the line is distortionless, the attenuation constant (in Np/m) is
A
500
B
5
C
0.014
D
0.002
3
GATE ECE 2010
MCQ (Single Correct Answer)
+1
-0.3
If the scattering matrix [S] of a two port network is $$$\left[ S \right] = \left[ {\matrix{ {0.2\,\angle \,\,{0^ \circ }} & {0.9\,\,\angle \,\,{{90}^ \circ }} \cr {0.9\,\angle \,\,{{90}^ \circ }} & {0.1\,\angle \,{{90}^ \circ }} \cr } } \right]$$$ then the network is
A
lossless and reciprocal
B
lossless but not reciprocal
C
not lossless but reciprocal
D
neither lossless nor reciprocal
4
GATE ECE 2010
MCQ (Single Correct Answer)
+2
-0.6
In the circuit shown, all the transmission line sections are lossless. The Voltage Standing Wave Ration (VSWR) on the 60W line is GATE ECE 2010 Electromagnetics - Transmission Lines Question 21 English
A
1.00
B
1.64
C
2.50
D
3.00
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