GATE ECE 2010 | GATE ECE Year Wise Previous Years Questions

GATE ECE 2010

MCQ (Single Correct Answer)

-0.6

The current I in the circuit shown is GATE ECE 2010 Network Theory - Sinusoidal Steady State Response Question 53 English

-j1 A

j1 A

0 A

20 A

GATE ECE 2010

MCQ (Single Correct Answer)

-0.3

For the two-port network shown below, the short-circuit admittance parameter matrix is GATE ECE 2010 Network Theory - Two Port Networks Question 50 English

GATE ECE 2010 Network Theory - Two Port Networks Question 50 English

$$\begin{bmatrix}4&-2\\-2&4\end{bmatrix}S$$

$$\begin{bmatrix}1&-0.5\\-0.5&1\end{bmatrix}S$$

$$\begin{bmatrix}1&0.5\\0.5&1\end{bmatrix}S$$

$$\begin{bmatrix}4&2\\2&4\end{bmatrix}S$$

GATE ECE 2010

MCQ (Single Correct Answer)

-0.6

In the circuit shown, the switch S is open for a long time and is closed at t=0. The current i(t) for t ≥ 0⁺ is GATE ECE 2010 Network Theory - Transient Response Question 20 English

GATE ECE 2010 Network Theory - Transient Response Question 20 English

i(t) = 0.5 - 0.125e^-1000t A

i(t) = 1.5 - 0.125e^-1000t A

i(t) = 0.5 - 0.5e^-1000t A

i(t) = 0.375e^-1000t A

GATE ECE 2010

MCQ (Single Correct Answer)

-0.3

The trigonometric Fourier series for the waveform f(t) shown below contains GATE ECE 2010 Signals and Systems - Representation of Continuous Time Signal Fourier Series Question 11 English

GATE ECE 2010 Signals and Systems - Representation of Continuous Time Signal Fourier Series Question 11 English

only cosine terms and zero value for the dc component

only cosine terms and a positive value for the dc component

only cosine terms and a negative value for the dc component

only sine terms and a negative for the dc component

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