1
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
With the usual notations, if the lengths of the sides of the triangle are 3 units, 5 units and 7 units, then the largest angle of the triangle is
A
$\dfrac{\pi}{2}$
B
$\dfrac{\pi}{3}$
C
$\dfrac{2\pi}{3}$
D
$\dfrac{\pi}{4}$
2
MHT CET 2026 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
In a right-angled $\triangle ABC$, the measures of the angles are in an Arithmetic Progression (A.P.) If its smallest side is $4$ units, then the area of $\triangle ABC$ is.....
A
$16$ sq. units
B
$8\sqrt{3}$ sq. units
C
$16\sqrt{3}$ sq. units
D
$32$ sq. units
3
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
In $\triangle ABC$, with usual notations, $(a + b + c)(b + c - a)(c + a - b)(a + b - c) = 3b^2c^2$, then $\angle A = $
A
$60^\circ$ or $120^\circ$
B
$30^\circ$ or $150^\circ$
C
$45^\circ$ or $135^\circ$
D
$30^\circ$ or $90^\circ$
4
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If ABC is a triangle of area $\Delta$ with $a = 2, b = \dfrac{7}{2}, c = \dfrac{5}{2}$, where $a, b, c$ are the lengths of the sides of the triangle opposite to angles A, B and C respectively, then $\dfrac{2\sin A - \sin 2A}{2\sin A + \sin 2A}$ is equal to...
A
$\dfrac{3}{4\Delta}$
B
$\left(\dfrac{3}{4\Delta}\right)^2$
C
$\dfrac{45}{4\Delta}$
D
$\left(\dfrac{45}{4\Delta}\right)^2$

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