1
MHT CET 2025 23rd April Morning Shift
MCQ (Single Correct Answer)
+2
-0

In $\triangle \mathrm{ABC}$, with usual notations, if $\cos \frac{B}{2}=\sqrt{\frac{c+a}{2 a}}$, then $a^2=$

A
$\mathrm{b}^2-\mathrm{c}^2$
B
$\mathrm{b}+\mathrm{c}$
C
$\mathrm{b}^2+\mathrm{c}^2$
D
$\mathrm{b}-\mathrm{c}$
2
MHT CET 2025 23rd April Morning Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle ABC with usual notations, $\cot \frac{\mathrm{A}}{2}+\cot \frac{\mathrm{B}}{2}+\cot \frac{\mathrm{C}}{2}=$

A
$\frac{\mathrm{s}^2}{\Delta}$, where $\Delta$ is the area of the triangle ABC .
B
$\frac{s}{\Delta}$, where $\Delta$ is the area of the triangle ABC .
C
$\frac{\Delta}{\mathrm{s}}$, where $\Delta$ is the area of the triangle ABC .
D
$\Delta$, where $\Delta$ is the area of the triangle ABC .
3
MHT CET 2025 23rd April Morning Shift
MCQ (Single Correct Answer)
+2
-0

With usual notations, in $\triangle \mathrm{ABC}$, the lengths of two sides are 10 cm and 9 cm respectively. If angles $\mathrm{A}, \mathrm{B}, \mathrm{C}$ are in A.P. then perimeter of $\triangle \mathrm{ABC}$ is

A
$24+2 \sqrt{6} \mathrm{~cm}$
B
$24+\sqrt{6} \mathrm{~cm}$
C
$24-2 \sqrt{6} \mathrm{~cm}$
D
$22-\sqrt{6} \mathrm{~cm}$
4
MHT CET 2025 23rd April Morning Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle ABC , with usual notations, if $\mathrm{a}=5, \mathrm{~b}=4, \cos (\mathrm{~A}-\mathrm{B})=\frac{31}{32}$, then $\mathrm{c}=$

A
6
B
7
C
5
D
2
MHT CET Subjects
EXAM MAP