1
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle ABC with usual notations if $|\overline{\mathrm{BC}}|=8,|\overline{\mathrm{CA}}|=7,|\overline{\mathrm{AB}}|=10$ then the projection of $\overline{\mathrm{AB}}$ on $\overline{\mathrm{AC}}$ is

A
$\frac{14}{85}$ units
B
$\frac{1}{85}$ units
C
$\frac{85}{14}$ units
D
$\frac{7}{85}$ units
2
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle ABC , the sides $\mathrm{a}, \mathrm{b}, \mathrm{c}$ are such that they are the roots of the equation $x^3-11 x^2+38 x-40=0$ Then

$$ \frac{\cos A}{a}+\frac{\cos B}{b}+\frac{\cos C}{c}= $$

A
$\frac{3}{4}$
B
1
C
$\frac{9}{16}$
D
$\frac{1}{16}$
3
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle ABC with usual notations if $\mathrm{a}=13$, $b=14, c=15$ Then $\sin A=$

A
$\frac{4}{5}$
B
$\frac{3}{5}$
C
$\frac{1}{2}$
D
$\frac{4}{7}$
4
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle $A B C$, with usual notations, $3 \mathrm{~b}=\mathrm{a}+\mathrm{c}$, then $\cot \frac{\mathrm{A}}{2} \cdot \cot \frac{\mathrm{C}}{2}=$

A
1
B
2
C
$\frac{1}{2}$
D
4
MHT CET Subjects
EXAM MAP