1
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle ABC , with usual notations if $\frac{2 \cos \mathrm{~A}}{\mathrm{a}}+\frac{\cos \mathrm{B}}{\mathrm{b}}+\frac{2 \cos \mathrm{C}}{\mathrm{c}}=\frac{\mathrm{a}}{\mathrm{bc}}+\frac{\mathrm{b}}{\mathrm{ca}}$ then $\angle \mathrm{A}=$

A
$\frac{\pi}{2}$
B
$\frac{\pi}{4}$
C
$\frac{\pi}{3}$
D
$\frac{\pi}{6}$
2
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle ABC with usual notations, if $\mathrm{a}, \mathrm{b}, \mathrm{c}$ are in arithmetic progression, then, $\tan \frac{\mathrm{A}}{2} \cdot \tan \frac{\mathrm{C}}{2}=$

A
3
B
$\frac{1}{13}$
C
-3
D
$\frac{1}{3}$
3
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

With usual notations, in a triangle $A B C$, if $\theta$ is any real number, then $a \cos (B-\theta)+b \cos (A+\theta)$ is

A
$a \cos \theta$
B
$\mathrm{b} \cos \theta$
C
$\cos \theta$
D
$c \cos \theta$
4
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

If two sides of a triangle are $\sqrt{3}-2$ and $\sqrt{3}+2$ units and their included angle is $60^{\circ}$, then the third side of the triangle is

A
15 units
B
$\sqrt{15}-2$ units
C
$\sqrt{15}+2$ units
D
$\sqrt{15}$ units
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