1
MHT CET 2025 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The smallest angle of the triangle whose sides are $6+\sqrt{12}, \sqrt{48}, \sqrt{24}$ is
A
$\frac{\pi}{2}$
B
$\frac{\pi}{6}$
C
$\frac{\pi}{4}$
D
$\frac{\pi}{3}$
2
MHT CET 2025 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
In a triangle $A B C$, with usual notations, if $\frac{b+c}{11}=\frac{c+a}{12}=\frac{a+b}{13}$ Then $\cos \mathrm{A}: \cos \mathrm{B}: \cos \mathrm{C}$ is
A
$7: 19: 25$
B
$19: 7: 25$
C
$12: 14: 20$
D
$19: 25: 20$
3
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle $\mathrm{ABC}, l(\mathrm{AB})=\sqrt{23}$ units, $l(\mathrm{BC})=3$ units, $l(\mathrm{CA})=4$ units, then $\frac{\cot A+\cot C}{\cot B}$ is

A
1
B
2
C
4
D
8
4
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle ABC , with usual notations, $2 \mathrm{ac} \sin \left(\frac{\mathrm{A}-\mathrm{B}+\mathrm{C}}{2}\right)$ is equal to

A
$\mathrm{a}^2+\mathrm{b}^2-\mathrm{c}^2$
B
$\mathrm{c}^2+\mathrm{a}^2-\mathrm{b}^2$
C
$\mathrm{b}^2-\mathrm{a}^2+\mathrm{c}^2$
D
$\mathrm{a^2-b^2-c^2}$
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