1
MHT CET 2023 12th May Evening Shift
+1
-0

When an inductor '$$L$$' and a resistor '$$R$$' in series are connected across a $$15 \mathrm{~V}, 50 \mathrm{~Hz}$$ a.c. supply, a current of $$0.3 \mathrm{~A}$$ flows in the circuit. The current differs in phase from applied voltage by $$\left(\frac{\pi}{3}\right)^c$$. The value of '$$R$$' is $$\left(\sin \frac{\pi}{6}=\cos \frac{\pi}{3}=\frac{1}{2}, \sin \frac{\pi}{3}=\cos \frac{\pi}{6}=\frac{\sqrt{3}}{2}\right)$$

A
$$10 \Omega$$
B
$$15 \Omega$$
C
$$20 \Omega$$
D
$$25 \Omega$$
2
MHT CET 2023 12th May Evening Shift
+1
-0

An a.c. source of $$15 \mathrm{~V}, 50 \mathrm{~Hz}$$ is connected across an inductor (L) and resistance (R) in series R.M.S. current of $$0.5 \mathrm{~A}$$ flows in the circuit. The phase difference between applied voltage and current is $$\left(\frac{\pi}{3}\right)$$ radian. The value of resistance $$(\mathrm{R})$$ is $$\left(\tan 60^{\circ}=\sqrt{3}\right)$$

A
$$10 \Omega$$
B
$$12 \Omega$$
C
$$15 \Omega$$
D
$$20 \Omega$$
3
MHT CET 2023 12th May Evening Shift
+1
-0

Resistor of $$2\Omega$$, inductor of $$100 \mu \mathrm{H}$$ and capacitor of $$400 \mathrm{pF}$$ are connected in series across a source of $$\mathrm{e}_{\mathrm{rms}}=0.1$$ Volt. At resonance, voltage drop across inductor is

A
25 V
B
2.5 V
C
250 V
D
20 V
4
MHT CET 2023 12th May Morning Shift
+1
-0

In the given circuit, r.m.s. value of current through the resistor $$\mathrm{R}$$ is

A
$$2 \mathrm{~A}$$
B
$$0.5 \mathrm{~A}$$
C
$$20 \mathrm{~A}$$
D
$$2 \sqrt{2} \mathrm{~A}$$
EXAM MAP
Medical
NEET