1
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

With the gradual increase in frequency of an a. c. source, the impedance of an LCR series circuit

A
first decreases, becomes minimum and then increases.
B
increases.
C
decreases.
D
remains constant.
2
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In series LCR circuit, the voltage across the inductance and the capacitance are not

A
out of phase with the voltage across the resistance by $$90^{\circ}$$.
B
equal in magnitude at resonance.
C
out of phase with each other by $$180^{\circ}$$.
D
in phase with the source voltage.
3
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

With an alternating voltage source of frequency '$$f$$', inductor '$$L$$', capacitor '$$C$$' and resistance '$$R$$' are connected in series. The voltage leads the current by $$45^{\circ}$$. The value of '$$L$$' is $$\left(\tan 45^{\circ}=1\right)$$

A
$$\left(\frac{1+2 \pi \mathrm{fCR}}{4 \pi^2 \mathrm{f}^2 \mathrm{C}}\right)$$
B
$$\left(\frac{1-2 \pi \mathrm{fCR}}{4 \pi^2 \mathrm{f}^2 \mathrm{C}}\right)$$
C
$$\left(\frac{4 \pi^2 \mathrm{f}^2 \mathrm{C}}{1+2 \pi \mathrm{fCR}}\right)$$
D
$$\left(\frac{4 \pi^2 \mathrm{f}^2 \mathrm{C}}{1-2 \pi \mathrm{fCR}}\right)$$
4
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The capacitive reactance of a capacitor '$$C$$' is $$\mathrm{X} \Omega$$. Both, the frequency of a.c. supply and capacitance of the above capacitor are doubled. The new capacitive reactance will be

A
$$\frac{\mathrm{X}}{4} \Omega$$
B
$$\frac{\mathrm{X}}{2} \Omega$$
C
$$2 \mathrm{X} \Omega$$
D
$$4 \mathrm{X} \Omega$$
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