1
MHT CET 2023 10th May Evening Shift
+1
-0

With an alternating voltage source of frequency '$$f$$', inductor '$$L$$', capacitor '$$C$$' and resistance '$$R$$' are connected in series. The voltage leads the current by $$45^{\circ}$$. The value of '$$L$$' is $$\left(\tan 45^{\circ}=1\right)$$

A
$$\left(\frac{1+2 \pi \mathrm{fCR}}{4 \pi^2 \mathrm{f}^2 \mathrm{C}}\right)$$
B
$$\left(\frac{1-2 \pi \mathrm{fCR}}{4 \pi^2 \mathrm{f}^2 \mathrm{C}}\right)$$
C
$$\left(\frac{4 \pi^2 \mathrm{f}^2 \mathrm{C}}{1+2 \pi \mathrm{fCR}}\right)$$
D
$$\left(\frac{4 \pi^2 \mathrm{f}^2 \mathrm{C}}{1-2 \pi \mathrm{fCR}}\right)$$
2
MHT CET 2023 10th May Evening Shift
+1
-0

The capacitive reactance of a capacitor '$$C$$' is $$\mathrm{X} \Omega$$. Both, the frequency of a.c. supply and capacitance of the above capacitor are doubled. The new capacitive reactance will be

A
$$\frac{\mathrm{X}}{4} \Omega$$
B
$$\frac{\mathrm{X}}{2} \Omega$$
C
$$2 \mathrm{X} \Omega$$
D
$$4 \mathrm{X} \Omega$$
3
MHT CET 2023 10th May Evening Shift
+1
-0

A $$100 \mathrm{~mH}$$ coil carries a current of $$1 \mathrm{~A}$$. Energy stored in the form of magnetic field is

A
0.025 J
B
0.050 J
C
0.075 J
D
0.100 J
4
MHT CET 2023 10th May Evening Shift
+1
-0

In the circuit given below, the current through inductor is $$0.9 \mathrm{~A}$$ and through the capacitor is $$0.6 \mathrm{~A}$$. The current drawn from the a.c. source is

A
1.5 A
B
0.9 A
C
0.6 A
D
0.3 A
EXAM MAP
Medical
NEET