MHT CET 2023 10th May Evening Shift | Alternating Current Question 79 | Physics

With an alternating voltage source of frequency '$$f$$', inductor '$$L$$', capacitor '$$C$$' and resistance '$$R$$' are connected in series. The voltage leads the current by $$45^{\circ}$$. The value of '$$L$$' is $$\left(\tan 45^{\circ}=1\right)$$

$$\left(\frac{1+2 \pi \mathrm{fCR}}{4 \pi^2 \mathrm{f}^2 \mathrm{C}}\right)$$

$$\left(\frac{1-2 \pi \mathrm{fCR}}{4 \pi^2 \mathrm{f}^2 \mathrm{C}}\right)$$

$$\left(\frac{4 \pi^2 \mathrm{f}^2 \mathrm{C}}{1+2 \pi \mathrm{fCR}}\right)$$

$$\left(\frac{4 \pi^2 \mathrm{f}^2 \mathrm{C}}{1-2 \pi \mathrm{fCR}}\right)$$

MHT CET 2023 10th May Evening Shift

MCQ (Single Correct Answer)

-0

The capacitive reactance of a capacitor '$$C$$' is $$\mathrm{X} \Omega$$. Both, the frequency of a.c. supply and capacitance of the above capacitor are doubled. The new capacitive reactance will be

$$\frac{\mathrm{X}}{4} \Omega$$

$$\frac{\mathrm{X}}{2} \Omega$$

$$2 \mathrm{X} \Omega$$

$$4 \mathrm{X} \Omega$$

MHT CET 2023 10th May Evening Shift

MCQ (Single Correct Answer)

-0

A $$100 \mathrm{~mH}$$ coil carries a current of $$1 \mathrm{~A}$$. Energy stored in the form of magnetic field is

0.025 J

0.050 J

0.075 J

0.100 J

MHT CET 2023 10th May Evening Shift

MCQ (Single Correct Answer)

-0

In the circuit given below, the current through inductor is $$0.9 \mathrm{~A}$$ and through the capacitor is $$0.6 \mathrm{~A}$$. The current drawn from the a.c. source is

MHT CET 2023 10th May Evening Shift Physics - Alternating Current Question 99 English

1.5 A

0.9 A

0.6 A

0.3 A

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