MHT CET 2023 13th May Evening Shift | Alternating Current Question 11 | Physics

In a $$L$$-$$R$$ circuit the inductive reactance is equal to the resistance $R$ in the circuit. An emf $$E=E_0 \cos \omega t$$ is applied to the circuit. The power consumed in the circuit is

$$\frac{E_0^2}{\sqrt{2} R}$$

$$\frac{E_0^2}{4 R}$$

$$\frac{E_0^2}{2 R}$$

$$\frac{E_0^2}{8 R}$$

MHT CET 2023 13th May Morning Shift

MCQ (Single Correct Answer)

-0

In an oscillating LC circuit, the maximum charge on the capacitor is '$$Q$$'. When the energy is stored equally between the electric and magnetic fields, the charge on the capacitor becomes

$$\frac{\mathrm{Q}}{4}$$

$$\mathrm{\frac{Q}{2}}$$

$$\frac{\mathrm{Q}}{\sqrt{2}}$$

$$\frac{\mathrm{Q}}{\sqrt{3}}$$

MHT CET 2023 13th May Morning Shift

MCQ (Single Correct Answer)

-0

With increase in frequency of a.c. supply, the impedance of an L-C-R series circuit

remains constant.

increases.

decreases.

decreases at first, becomes minimum and then increases.

MHT CET 2023 13th May Morning Shift

MCQ (Single Correct Answer)

-0

In an a.c. circuit the instantaneous current and emf are represented as $$\mathrm{I}=\mathrm{I}_0, \sin [\omega \mathrm{t}-\pi / 6]$$ and $$\mathrm{E}=\mathrm{E}_0 \sin [\omega \mathrm{t}+\pi / 3]$$ respectively. The voltage leads the current by

$$\frac{\pi}{2}$$

$$\frac{\pi}{4}$$

$$\frac{\pi}{3}$$

$$\frac{\pi}{6}$$

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