1
MHT CET 2021 22th September Morning Shift
+1
-0

An a.c. source of angular frequency '$$\omega$$' is fed across a resistor '$$R$$' and a capacitor '$$C$$' in series. The current registered is I. If now the frequency of source is changed to $$\frac{\omega}{3}$$ (but maintaining the same voltage), the current in the circuit is found to be halved. The ratio of reactance to resistance at the original frequency '$$\omega$$' will be

A
$$\sqrt{\frac{2}{5}}$$
B
$$\sqrt{\frac{1}{5}}$$
C
$$\sqrt{\frac{4}{5}}$$
D
$$\sqrt{\frac{3}{5}}$$
2
MHT CET 2021 22th September Morning Shift
+1
-0

In an a.c. circuit, a resistance R = 40 $$\Omega$$ and an inductance 'L' are connected in series. If the phase angle between voltage and current is 45$$^\circ$$, then the value of the inductive reactance is (tan 45$$^\circ$$ = 1)

A
50$$\Omega$$
B
40$$\Omega$$
C
10$$\Omega$$
D
20$$\Omega$$
3
MHT CET 2021 22th September Morning Shift
+1
-0

The frequency of the output signal of an LC oscillator circuit is '$$\mathrm{F}$$' Hz with a capacitance of 0.1 $$\mu \mathrm{F}$$. If the value of the capacitor is increased to $$0.2~ \mu \mathrm{F}$$, then the frequency of the output signal will be

A
$$\frac{\mathrm{F}}{\sqrt{2}} \mathrm{~Hz}$$
B
$$\frac{\mathrm{F}}{\sqrt{3}} \mathrm{~Hz}$$
C
$$\frac{\mathrm{F}}{2} \mathrm{~Hz}$$
D
$$2 \mathrm{~F} \mathrm{~Hz}$$
4
MHT CET 2021 21th September Evening Shift
+1
-0

In LCR series resonant circuit, at resonance, voltage across 'L' and 'C' will cancel each other because they are

A
90$$^\circ$$ out of phase
B
90$$^\circ$$ in phase
C
180$$^\circ$$ in phase
D
180$$^\circ$$ out of phase
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