MHT CET 2024 15th May Morning Shift | Alternating Current Question 12 | Physics

When a coil is connected to a d.c. source of e.m.f. 12 volt; then the current of 4 A flows in it . If the same coil is connected to a 12 volt, 50 Hz a.c. source, then the current flowing in it is 2.4 A . Then self-inductance of the coil will be

48 H

12 H

$\frac{4}{\pi} \times 10^{-2} \mathrm{H}$

$\frac{8}{\pi} \times 10^{-2} \mathrm{H}$

MHT CET 2024 15th May Morning Shift

MCQ (Single Correct Answer)

-0

In an a.c. circuit, the reactance of a coil is $\sqrt{3}$ times its resistance. The phase difference between the voltage across the coil to the current through the coil will be

$\tan ^{-1}(0)$

$\tan ^{-1} \frac{1}{\sqrt{3}}$

$\tan ^{-1}(1)$

$\tan ^{-1}(\sqrt{3})$

MHT CET 2024 15th May Morning Shift

MCQ (Single Correct Answer)

-0

A series $\mathrm{L}-\mathrm{C}-\mathrm{R}$ circuit containing a resistance ' $R$ ' has angular frequency ' $\omega$ '. At resonance the voltage across resistance and inductor are ' $V_R$ ' and ' $\mathrm{V}_{\mathrm{L}}$ ' respectively, then value of capacitance will be

$\frac{V_R}{V_L \omega R}$

$\frac{V_L}{V_R R \omega^2}$

$\frac{V_R}{V_L R \omega^2}$

$\frac{V_L R}{V_R \omega}$

MHT CET 2024 15th May Morning Shift

MCQ (Single Correct Answer)

-0

Alternating current of peak value $\left(\frac{2}{\pi}\right)$ A flows through the primary coil of a transformer. The coefficient of mutual inductance between primary and secondary coils is 1 H . The peak e.m.f. induced in secondary coil (Frequency of a.c. $=50 \mathrm{~Hz}$ )

50 V

100 V

150 V

200 V

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