MHT CET 2023 10th May Evening Shift | Rotational Motion Question 21 | Physics

The moment of inertia of a uniform square plate about an axis perpendicular to its plane and passing through the centre is $$\frac{\mathrm{Ma}^2}{6}$$, where '$$M$$' is the mass and '$$a$$' is the side of square plate. Moment of inertia of this plate about an axis perpendicular to its plane and passing through one of its corners is

$$\frac{\mathrm{Ma}^2}{6}$$

$$\frac{2 \mathrm{Ma}^2}{3}$$

$$\frac{\mathrm{Ma}^2}{3}$$

$$\frac{2 \mathrm{Ma}^2}{5}$$

MHT CET 2023 10th May Morning Shift

MCQ (Single Correct Answer)

-0

If 'I' is moment of inertia of a thin circular disc about an axis passing through the tangent of the disc and in the plane of disc. The moment of inertia of same circular disc about an axis perpendicular to plane and passing through its centre is

$$\frac{4I}{5}$$

$$\frac{2I}{5}$$

$$\frac{4I}{3}$$

$$\frac{2I}{3}$$

MHT CET 2023 10th May Morning Shift

MCQ (Single Correct Answer)

-0

Seven identical discs each of mass $$M$$ and radius $$\mathrm{R}$$ are arranged in a hexagonal plane pattern so as to touch each neighbour disc as shown in the figure. The moment of inertia of the system of seven discs about an axis passing through the centre of central disc and normal to the plane of all discs is

MHT CET 2023 10th May Morning Shift Physics - Rotational Motion Question 19 English

$$\frac{7}{2} \mathrm{~MR}^2$$

$$\frac{13}{2} \mathrm{~MR}^2$$

$$\frac{29}{2} \mathrm{~MR}^2$$

$$\frac{55}{2} \mathrm{~MR}^2$$

MHT CET 2023 10th May Morning Shift

MCQ (Single Correct Answer)

-0

A particle of mass '$$\mathrm{m}$$' is rotating along a circular path of radius '$$r$$' having angular momentum '$$L$$'. The centripetal force acting on the particle is given by

$$\frac{\mathrm{L}^2}{\mathrm{mr}}$$

$$\frac{\mathrm{L}^2}{\mathrm{mr}^2}$$

$$\frac{\mathrm{mL}^2}{\mathrm{r}}$$

$$\frac{\mathrm{L}^2}{\mathrm{mr}^3}$$

PREVIOUS NEXT

MHT CET Subjects