MHT CET 2023 11th May Morning Shift | Rotational Motion Question 86 | Physics

Radius of gyration of a thin uniform circular disc about the axis passing through its centre and perpendicular to its plane is $$\mathrm{K}_{\mathrm{c}}$$. Radius of gyration of the same disc about a diameter of the disc is $$K_d$$. The ratio $$K_c: K_d$$ is

$$\sqrt{2}: 1$$

$$1: \sqrt{2}$$

$$2: 1$$

$$1: 4$$

MHT CET 2023 11th May Morning Shift

MCQ (Single Correct Answer)

-0

A disc has mass $$M$$ and radius $$R$$. How much tangential force should be applied to the rim of the disc, so as to rotate with angular velocity '$$\omega$$' in time $$\mathrm{t}$$ ?

$$\frac{M R \omega}{4 t}$$

$$\frac{\mathrm{MR} \omega}{2 \mathrm{t}}$$

$$\frac{\mathrm{MR} \omega}{\mathrm{t}}$$

$$\mathrm{MR} \omega \mathrm{t}$$

MHT CET 2023 10th May Evening Shift

MCQ (Single Correct Answer)

-0

What is the moment of inertia of the electron moving in second Bohr orbit of hydrogen atom? [ $$\mathrm{h}=$$ Planck's constant, $$\mathrm{m}=$$ mass of electron, $$\varepsilon_0=$$ permittivity of free space, $$\mathrm{e}=$$ charge on electron]

$$\frac{4 \varepsilon_0^2 h^4}{\pi^2 m e^4}$$

$$\frac{8 m \varepsilon_0^2 h^4}{\pi^2 e^4}$$

$$\frac{16 \varepsilon_0^2 h^4}{\pi^2 m e^4}$$

$$\frac{\varepsilon_0^2 h^4}{16 \pi^2 \mathrm{me}^4}$$

MHT CET 2023 10th May Evening Shift

MCQ (Single Correct Answer)

-0

Two spheres each of mass '$$M$$' and radius $$\frac{R}{2}$$ are connected at the ends of massless rod of length '$$2 R$$'. What will be the moment of inertia of the system about an axis passing through centre of one of the spheres and perpendicular to the rod?

$$\frac{2}{3} \mathrm{MR}^2$$

$$\frac{5}{2} \mathrm{MR}^2$$

$$\frac{5}{21} \mathrm{MR}^2$$

$$\frac{21}{5} \mathrm{MR}^2$$

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