1
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle PQR with usual notations, $\angle \mathrm{R}=\frac{\pi}{2}$. If $\tan \frac{\mathrm{P}}{2}$ and $\tan \frac{\mathrm{Q}}{2}$ are the roots of the equation $a x^2+b x+c=0(a \neq 0)$, then

A

$\mathrm{a}+\mathrm{b}=\mathrm{c}$

B

$\mathrm{b}+\mathrm{c}=\mathrm{a}$

C

$\mathrm{a}+\mathrm{c}=\mathrm{b}$

D

$\mathrm{b}=\mathrm{c}$

2
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

If the angles $\mathrm{A}, \mathrm{B}$ and C of a triangle are in A.P. and if $\mathrm{a}, \mathrm{b}$ and c denote the length of the sides opposite to $\mathrm{A}, \mathrm{B}$ and C respectively, then the value of $\frac{a}{b} \sin 2 B+\frac{b}{a} \sin 2 A$ is

A
$\sqrt{3}$
B
$\frac{\sqrt{3}}{2}$
C
$\frac{1}{\sqrt{3}}$
D
$\frac{1}{2}$
3
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle $A B C$, with usual notations, if $a=5$, $\mathrm{b}=7 \sin \mathrm{~A}=\frac{3}{4}$, then total number of triangles possible are

A
1
B
0
C
2
D
5
4
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle $A B C$, with usual notations, $\cot \left(\frac{A+B}{2}\right) \cdot \tan \left(\frac{A-B}{2}\right)=$

A
$\frac{a+b}{a-b}$
B
$\frac{a-b}{a+b}$
C
$\frac{a}{a+b}$
D
$\frac{b}{a-b}$

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