1
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If ABC is a triangle of area $\Delta$ with $a = 2, b = \dfrac{7}{2}, c = \dfrac{5}{2}$, where $a, b, c$ are the lengths of the sides of the triangle opposite to angles A, B and C respectively, then $\dfrac{2\sin A - \sin 2A}{2\sin A + \sin 2A}$ is equal to...
A
$\dfrac{3}{4\Delta}$
B
$\left(\dfrac{3}{4\Delta}\right)^2$
C
$\dfrac{45}{4\Delta}$
D
$\left(\dfrac{45}{4\Delta}\right)^2$
2
MHT CET 2026 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
In $\triangle ABC$, with usual notations, if the sides $a$, $b$ and $c$ are in the ratio $18 : 17 : 7$, then $\cot\dfrac{A}{2} : \cot\dfrac{B}{2} : \cot\dfrac{C}{2} =$
A
$4 : 3 : 14$
B
$14 : 4 : 3$
C
$3 : 4 : 14$
D
$4 : 14 : 3$
3
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
In $\triangle ABC$, with usual notations, if $\Delta$ denotes the area of triangle $ABC$ then the value of $2s(b+c-a)\tan\left(\dfrac{A}{2}\right)$ is equal to $\ldots$
A
$\Delta$
B
$2\Delta$
C
$3\Delta$
D
$4\Delta$
4
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
In $\triangle ABC$, if $\angle C = \dfrac{\pi}{3}$, then the value of $\cos^2 A + \cos^2 B + \cos A\cos B$ is...
A
$\dfrac{3}{4}$
B
$\dfrac{5}{4}$
C
$\dfrac{-3}{4}$
D
$\dfrac{-5}{4}$

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