1
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
For the linear programming problem, $x + 2y \leq 10,\ 3x + y \leq 12,\ x, y \geq 0$, the maximum value of $z = 5x + 10y$ occurs at every point on the line segment joining the points..
A
$(0,0)$ and $(4,0)$
B
$(0,0)$ and $(0,5)$
C
$(4,0)$ and $\left(\dfrac{14}{5}, \dfrac{18}{5}\right)$
D
$(0,5)$ and $\left(\dfrac{14}{5}, \dfrac{18}{5}\right)$
2
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The region satisfying the inequalities $y - x \geq 2,\ x + y \leq 5,\ x \geq 0$ and $y \geq 0$ is
A
MHT CET 2026 17th April Morning Shift Mathematics - Linear Programming Question 5 English Option 1
B
MHT CET 2026 17th April Morning Shift Mathematics - Linear Programming Question 5 English Option 2
C
MHT CET 2026 17th April Morning Shift Mathematics - Linear Programming Question 5 English Option 3
D
MHT CET 2026 17th April Morning Shift Mathematics - Linear Programming Question 5 English Option 4
3
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The minimum value of $z = 3x + 5y$, subject to constraints $x \leq 80$, $y \geq 60$, $x + y \leq 200$ & $x, y \geq 0$ occurs at the point...
A
$(0, 200)$
B
$(60, 0)$
C
$(0, 60)$
D
$(80, 60)$
4
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The feasible region represented by the constraints $y - 2x \leq 4, x + y \geq 5, x \leq 4, y \geq 2, x, y \geq 0$ is ...........
A
a convex bounded region with 4 corner points
B
an unbounded region
C
a convex bounded region with 5 corner points
D
no feasible region

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