MHT CET 2023 10th May Evening Shift | Linear Programming Question 25 | Mathematics

The shaded area in the figure given below is a solution set of a system of inequations. The minimum value of objective function $$3 x+5 y$$, subject to the linear constraints given by this system of inequations is

MHT CET 2023 10th May Evening Shift Mathematics - Linear Programming Question 40 English

19.5

19.8

MHT CET 2023 10th May Morning Shift

MCQ (Single Correct Answer)

-0

The vertices of the feasible region for the constraints $$x+y \leq 4, x \leq 2, y \leq 1, x+y \geq 1, x, y \geq 0$$ are

$$(1,0),(2,0),(2,1),(0,4)$$

$$(0,1),(4,0),(0,4),(1,0)$$

$$(1,0),(2,0),(2,1),(0,1)$$

$$(1,0),(4,0),(2,1),(0,4)$$

MHT CET 2023 9th May Evening Shift

MCQ (Single Correct Answer)

-0

The graphical solution set for the system of inequations $$x-2 y \leq 2,5 x+2 y \geq 10,4 x+5 y \leq 20, x \geq 0, y \geq 0$$ is given by

MHT CET 2023 9th May Evening Shift Mathematics - Linear Programming Question 41 English

Fig. 2

Fig. 4

Fig. 1

Fig. 3

MHT CET 2023 9th May Morning Shift

MCQ (Single Correct Answer)

-0

If feasible region is as shown in the figure, then the related inequalities are

MHT CET 2023 9th May Morning Shift Mathematics - Linear Programming Question 42 English

$$3 x+4 y \geq 12, y-x \geq 0, y \leq 3, x, y \geq 0$$

$$3 x+4 y \leq 12, y-x \leq 0, y \geq 3, x, y \geq 0$$

$$3 x+4 y \leq 12, y-x \geq 0, y \leq 3, x, y \geq 0$$

$$3 x+4 y \geq 12, y-x \leq 0, y \geq 3, x, y \geq 0$$

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