1
GATE EE 2014 Set 1
+1
-0.3
A 2-bus system and corresponding zero sequence network are shown in the figure.

The transformers T1 and T2 are connected as

A
B
C
D
2
GATE EE 2012
+1
-0.3
The sequence components of the fault current are as follows:
$${{\rm I}_{positive}} = j1.5\,pu,\,\,{{\rm I}_{negative}} = - j0.5\,\,pu,$$
$${{\rm I}_{zero}} = - j1\,\,pu.$$ The typeof fault in the system is
A
$$LG$$
B
$$LL$$
C
$$LLG$$
D
$$LLLG$$
3
GATE EE 2008
+1
-0.3
A 3-phase transmission line is shown in figure:

Voltage drop across the transmission line is given by the following equation: $$\left[ {\matrix{ {\Delta {V_a}} \cr {\Delta {V_b}} \cr {\Delta {V_c}} \cr } } \right] = \left[ {\matrix{ {{Z_s}} & {{Z_m}} & {{Z_m}} \cr {{Z_m}} & {{Z_s}} & {{Z_m}} \cr {{Z_m}} & {{Z_m}} & {{Z_s}} \cr } } \right]\left[ {\matrix{ {{i_a}} \cr {{i_b}} \cr {{i_c}} \cr } } \right]$$\$
Shunt capacitance of the line can be neglect. If the line has positive sequence impedance of $$15\,\,\Omega$$ and zero sequence in impedance of $$48\,\,\Omega ,$$ then the values of $${{Z_s}}$$ and $${{Z_m}}$$ will be

A
$${Z_s} = 31.5\,\Omega ;\,\,{Z_m} = 16.5\,\Omega$$
B
$${Z_s} = 26\,\Omega ;\,\,{Z_m} = 11\,\Omega$$
C
$${Z_s} = 16.5\,\Omega ;\,\,{Z_m} = 31.5\,\Omega$$
D
$${Z_s} = 11\,\Omega ;\,\,{Z_m} = 26\,\Omega$$
4
GATE EE 1997
+1
-0.3
For a fault at the terminals of a synchronous generator, the fault current is maximum for a
A
3-phase fault
B
3-phase to ground fault
C
line-to ground fault
D
line-to-line fault
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