1
GATE EE 2008
MCQ (Single Correct Answer)
+1
-0.3
A 3-phase transmission line is shown in figure:

Voltage drop across the transmission line is given by the following equation: $$\left[ {\matrix{ {\Delta {V_a}} \cr {\Delta {V_b}} \cr {\Delta {V_c}} \cr } } \right] = \left[ {\matrix{ {{Z_s}} & {{Z_m}} & {{Z_m}} \cr {{Z_m}} & {{Z_s}} & {{Z_m}} \cr {{Z_m}} & {{Z_m}} & {{Z_s}} \cr } } \right]\left[ {\matrix{ {{i_a}} \cr {{i_b}} \cr {{i_c}} \cr } } \right]$$\$
Shunt capacitance of the line can be neglect. If the line has positive sequence impedance of $$15\,\,\Omega$$ and zero sequence in impedance of $$48\,\,\Omega ,$$ then the values of $${{Z_s}}$$ and $${{Z_m}}$$ will be

A
$${Z_s} = 31.5\,\Omega ;\,\,{Z_m} = 16.5\,\Omega$$
B
$${Z_s} = 26\,\Omega ;\,\,{Z_m} = 11\,\Omega$$
C
$${Z_s} = 16.5\,\Omega ;\,\,{Z_m} = 31.5\,\Omega$$
D
$${Z_s} = 11\,\Omega ;\,\,{Z_m} = 26\,\Omega$$
2
GATE EE 1997
MCQ (Single Correct Answer)
+1
-0.3
For a fault at the terminals of a synchronous generator, the fault current is maximum for a
A
3-phase fault
B
3-phase to ground fault
C
line-to ground fault
D
line-to-line fault
3
GATE EE 1996
MCQ (Single Correct Answer)
+1
-0.3
For an unbalanced fault, with paths for zero sequence currents, at the point of fault
A
The negative and zero sequence voltages are minimum.
B
The negative and zero sequence voltages are maximum.
C
The negative sequence voltage is minimum and zero sequence voltage is maximum.
D
The negative sequence voltage is maximum and zero sequence voltage is minimum.
4
GATE EE 1995
Fill in the Blanks
+1
-0
The positive sequence component of the voltage at the point of fault in a power system is zero for a _________fault.
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