1
JEE Advanced 2026 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1

A beam of polychromatic light passes through a thin prism of prism angle $6^{\circ}$. The refractive index of the material of the prism varies with wavelength $(\lambda)$ as $n(\lambda) = \alpha \lambda + \frac{\beta}{\lambda^2}$, where $\alpha = 3\ \mu m^{-1}$ and $\beta = 0.096\ \mu m^2$. If $\lambda_{min}$ is the wavelength at which the angle of minimum deviation $D_m$ is smallest, then the correct value of $D_m$ at $\lambda_{min}$ is :

A

6.4°

B

4.8°

C

3.2°

D

2.4°

2
JEE Advanced 2026 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1

A particle of mass m, and angular momentum is moving in a circular orbit of radius r0 under the influence of an attractive force $\vec{F}(r)=-\frac{k}{r^2} \hat{r}$. Keeping its angular momentum unchanged, the particle is displaced radially by a small distance $\delta r \ll r_0$, due to which its radial distance varies periodically. The corresponding time period is :

A

$\frac{2 \pi \ell^3}{mk^2}$

B

$2\pi \sqrt{\frac{m}{k}}$

C

$\frac{2 \pi \ell^3}{3mk^2}$

D

$\frac{2 \pi \ell^3}{5mk^2}$

3
JEE Advanced 2026 Paper 2 Online
MCQ (More than One Correct Answer)
+4
-1
Consider two isosceles prisms 1 and 2 with prism angles $A_1$ and $A_2$ and refractive indices $n_1$ and $n_2$, respectively, as shown in the figure. The faces $a_1 b_1$ and $a_2 b_2$ are parallel to each other and perpendicular to the mirror $M$. If a ray of light is incident on the face $a_1 c_1$ and emerges from the face $a_2 c_2$, then the correct statement(s) is/are : JEE Advanced 2026 Paper 2 Online Physics - Geometrical Optics Question 1 English
A

If both the prisms are at minimum deviation condition, then $\dfrac{n_2}{n_1} = \dfrac{\sin\left(\dfrac{A_1}{2}\right)}{\sin\left(\dfrac{A_2}{2}\right)}$.

B

If prism 2 is at minimum deviation condition, then $\sin i_1 = n_2 \sin \left(\dfrac{A_2}{2}\right)$ is always true.

C

If both the prisms 1 and 2 are thin and are at minimum deviation condition with angles of deviation $\delta_{m1}$ and $\delta_{m2}$, respectively, then $\theta = \dfrac{\delta_{m1}}{2(n_1 - 1)} + \dfrac{\delta_{m2}}{2(n_2 - 1)}$.

D

If prism 1 is at minimum deviation condition, then $\sin i_2 = n_1 \sin \left(\dfrac{A_1}{2}\right)$ is always true.

4
JEE Advanced 2026 Paper 2 Online
MCQ (More than One Correct Answer)
+4
-1

In a vacuum chamber, a particle of charge $1\ \mu C$ and mass $1\ \mathrm{mg}$ is projected with a velocity $(\hat{i} + 2\hat{j})\ \mathrm{ms}^{-1}$ from the $XZ$ plane at time $t = 0$ in an electric field of $1\hat{i}\ \mathrm{Vm}^{-1}$. At $t = 0.2\ s$, the electric field is switched off and a magnetic field of $6\hat{j}\ \mathrm{T}$ is switched on. The acceleration due to gravity is $-10\hat{j}\ \mathrm{ms}^{-2}$. Correct option(s) is/are :

A

The vertical distance of the particle from the $XZ$ plane at $t = 0.3\ s$ is $15\ \mathrm{cm}$.

B

The vertical distance of the particle from the $XZ$ plane at $t = 0.4\ s$ is $10\ \mathrm{cm}$.

C

The radius of the trajectory of the particle for $t > 0.2\ s$ is $20\ \mathrm{cm}$.

D

The particle will be in the $XZ$ plane at $t = 0.35\ s$.

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