1
JEE Advanced 2026 Paper 2 Online
Numerical
+2
-0

Consider the ellipses given by

$$ x^2+4 y^2=1 \quad \text { and } \quad 4 x^2+y^2=1 $$

Let $P$ be the point in the first quadrant where the given ellipses intersect. If $\theta$ is the acute angle between the tangents to the given ellipses at the point $P$, then the value of $4 \tan \theta$ is $\_\_\_\_$ .

Your input ____
2
JEE Advanced 2026 Paper 2 Online
Numerical
+2
-0

Consider the ellipses given by

$$ x^2+4 y^2=1 \quad \text { and } \quad 4 x^2+y^2=1 . $$

If $\alpha$ is the area of the common region that lies inside both the given ellipses, then the value of $\cot \alpha$ is $\_\_\_\_$ .

Your input ____
3
JEE Advanced 2026 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1

A metal wire of cross-sectional area 0.5 mm2 and length 100 m is connected across a battery of e.m.f. 2 V and internal resistance 1 Ω. The density, atomic mass and electrical conductivity of the metal are 6.35 × 103 kg m−3, 63.5 gm/mole and 2 × 108 mho m−1, respectively. Assuming one conduction electron per atom of the metal, the drift velocity (in mm s−1) of the electrons in the wire is:

[Take Avogadro’s number as 6 × 1023 and charge of the electron as 1.6 × 10−19 C.]

A

0.052

B

0.104

C

0.208

D

0.156

4
JEE Advanced 2026 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1

A nuclear reactor starts producing a radioactive nuclide X from t = 0, at a constant rate of α per second. Each decay of X produces energy E0, which is utilized to heat a liquid of mass m and specific heat s. Assuming no heat loss from the liquid and taking λ as the decay constant of X, the rate of increase in the temperature of the liquid is :

A

$ \frac{\alpha E_0}{ms} (1 - e^{-\lambda t}) $

B

$ \frac{\alpha E_0}{ms} (e^{\lambda t} - 1) $

C

$ \frac{\lambda E_0}{ms} (1 - e^{-\lambda t}) $

D

$ \frac{E_0}{ms} (\alpha - \lambda e^{-\lambda t}) $

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