1
IIT-JEE 2011 Paper 1 Offline
+4
-1
A straight line $$L$$ through the point $$(3, -2)$$ is inclined at an angle $${60^ \circ }$$ to the line $$\sqrt {3x} + y = 1.$$ If $$L$$ also intersects the x-axis, then the equation of $$L$$ is
A
$$y + \sqrt {3x} + 2 - 3\sqrt 3 = 0$$
B
$$y - \sqrt {3x} + 2 + 3\sqrt 3 = 0$$
C
$$\sqrt {3y} - x + 3 + 2\sqrt 3 = 0$$
D
$$\sqrt {3y} + x - 3 + 2\sqrt 3 = 0$$
2
IIT-JEE 2011 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Let the eccentricity of the hyperbola $${{{x^2}} \over {{a^2}}} - {{{y^2}} \over {{b^2}}} = 1$$ be reciprocal to that of the ellipse $${x^2} + 4{y^2} = 4$$. If the hyperbola passes through a focus of the ellipse, then
A
the equation of the hyperbola is $${{{x^2}} \over 3} - {{{y^2}} \over 2} = 1$$
B
a focus of the hyperbola is $$(2, 0)$$
C
theeccentricity of the hyperbola is $$\sqrt {{5 \over 3}}$$
D
The equation of the hyperbola is $${x^2} - 3{y^2} = 3$$
3
IIT-JEE 2011 Paper 1 Offline
Numerical
+4
-0
Consider the parabola $${y^2} = 8x$$. Let $${\Delta _1}$$ be the area of the triangle formed by the end points of its latus rectum and the point $$P\left( {{1 \over 2},2} \right)$$ on the parabola and $${\Delta _2}$$ be the area of the triangle formed by drawing tangents at $$P$$ and at the end points of the latus rectum. Then $${{{\Delta _1}} \over {{\Delta _2}}}$$ is
4
IIT-JEE 2011 Paper 1 Offline
Numerical
+4
-0
Let $$f\left( \theta \right) = \sin \left( {{{\tan }^{ - 1}}\left( {{{\sin \theta } \over {\sqrt {\cos 2\theta } }}} \right)} \right),$$ where $$- {\pi \over 4} < \theta < {\pi \over 4}.$$

Then the value of $${d \over {d\left( {\tan \theta } \right)}}\left( {f\left( \theta \right)} \right)$$ is

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