1
IIT-JEE 2007 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

Let $$\alpha,\beta$$ be the roots of the equation $$x^2-px+r=0$$ and $$\frac{\alpha}{2},2\beta$$ be the roots of the equation $$x^2-qx+r=0$$. Then the value of r is

A
$$\frac{2}{9}(p-q)(2q-p)$$
B
$$\frac{2}{9}(q-p)(2p-q)$$
C
$$\frac{2}{9}(q-2p)(2q-p)$$
D
$$\frac{2}{9}(2p-q)(2q-p)$$
2
IIT-JEE 2007 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

Let $$f(x)$$ be differentiable on the interval (0, $$\infty$$) such that $$f(1)=1$$, and $$\mathop {\lim }\limits_{t \to x} {{{t^2}f(x) - {x^2}f(t)} \over {t - x}} = 1$$ for each $$x > 0$$. Then $$f(x)$$ is

A
$${1 \over {3x}} + {{2{x^2}} \over 3}$$
B
$$ - {1 \over {3x}} + {{4{x^2}} \over 3}$$
C
$$ - {1 \over x} + {2 \over {{x^2}}}$$
D
$${1 \over x}$$
3
IIT-JEE 2007 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

One Indian and four American men and their wives are to be seated randomly around a circular table. Then the conditional probability that the Indian man is seated adjacent to his wife given that each American man is seated adjacent to his wife is

A
$$\frac{1}{2}$$
B
$$\frac{1}{3}$$
C
$$\frac{2}{5}$$
D
$$\frac{1}{5}$$
4
IIT-JEE 2007 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

The tangent to the curve $$y=e^x$$ drawn at the point ($$c,e^c$$) intersects the line joining the points ($$c-1,e^{c-1}$$) and ($$c+1,e^{c+1}$$)

A
on the left of $$x=c$$
B
on the right of $$x=c$$
C
at no point
D
at all points

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