$\mathrm{RCONH}_2$ is converted into $\mathrm{RNH}_2$ by means of Hofmann bromamide degradation.

In this reaction, RCONHBr is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.

How can the conversion of (i) to (ii) be brought about?

$\mathrm{RCONH}_2$ is converted into $\mathrm{RNH}_2$ by means of Hofmann bromamide degradation.

In this reaction, RCONHBr is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.

Which is the rate determining step in Hofmann bromamide degradation?

$\mathrm{RCONH}_2$ is converted into $\mathrm{RNH}_2$ by means of Hofmann bromamide degradation.

In this reaction, RCONHBr is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.

What are the constituent amines formed when the mixture of (i) and (ii) undergoes Hofmann bromamide degradation?

The coordination of $$\mathrm{Ni^2+}$$ is 4.

$$\mathrm{NiCl_2+KCN}$$ (excess) $$\to$$ A (cyano complex)

$$\mathrm{NiCl_2+ conc.~HCl}$$ (excess) $$\to$$ B (chloro complex)

Predict the magnetic nature of $\mathbf{A}$ and $\mathbf{B}$.