1
IIT-JEE 2006
MCQ (Single Correct Answer)
+3
-1

Consider a cylindrical element as shown in the figure. The current that flows through the element is I and resistivity of material of the cylinder is $\rho$. Choose the correct option out the following

IIT-JEE 2006 Physics - Current Electricity Question 3 English
A

Power loss in first half is four times the power loss in second half.

B

Voltage drop in first half is 4 times of voltage drop in second half.

C

Current density in both halves are equal.

D

Electric field in both halves is equal

2
IIT-JEE 2006
MCQ (More than One Correct Answer)
+3
-1

In the given diagram, a line of force of a particular force field is shown. Out of the following options, it can never represent

IIT-JEE 2006 Physics - Current Electricity Question 4 English
A

an electrostatic field.

B

a magnetostatic field.

C

a gravitational field of a mass at rest.

D

an induced electric field

3
IIT-JEE 2006
MCQ (More than One Correct Answer)
+3
-1

The electrostatic potential $\left(\phi_r\right)$ of a spherical symmetric system, kept at origin, is shown in the adjacent figure, and given as

$$ \begin{array}{ll} \phi_r=\frac{q}{4 \pi \epsilon_0 r} & \left(r \geq \mathrm{R}_0\right) \\ \phi_r=\frac{q}{4 \pi \epsilon_0 \mathrm{R}_0} & \left(r \leq \mathrm{R}_0\right) \end{array} $$

IIT-JEE 2006 Physics - Electrostatics Question 3 English

Which of the following option(s) is/are correct?
A

For spherical region $r \leq \mathrm{R}_0$, the total electrostatic energy stored is zero.

B

Within $r=2 \mathrm{R}_0$, the total charge is $q$.

C

There will be no charge anywhere except at $r=\mathrm{R}_0$.

D

Electric field is discontinuous at $r=\mathrm{R}_0$.

4
IIT-JEE 2006
MCQ (More than One Correct Answer)
+3
-1

A solid cylinder of mass m and radius $r$ is rolling on rough inclined plane of inclination $\theta$. The coefficient of friction between the cylinder and incline is $\mu$. then

A

frictional force is always $\mu \mathrm{mg} \cos \theta$.

B

friction is a dissipative force.

C

by decreasing $\theta$, frictional force decreases.

D

friction opposes translation and supports rotation.

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