1
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two sound waves each of wavelength ' $\lambda$ ' and having the same amplitude ' $A$ ' from two source ' $\mathrm{S}_1$ ' and ' $\mathrm{S}_2$ ' interfere at a point P . If the path difference, $\mathrm{S}_2 \mathrm{P}-\mathrm{S}_1 \mathrm{P}=\lambda / 3$ then the amplitude of resultant wave at point ' P ' will be $\left[\cos \left(120^{\circ}\right)=-0.5\right]$

A
$\mathrm{A}$
B
$\mathrm{2 A}$
C
$\frac{\mathrm{A}}{2}$
D
$\frac{3 \mathrm{A}}{2}$
2
MHT CET 2024 15th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Sodium light $\left(\lambda=6 \times 10^{-7} \mathrm{~m}\right)$ is used to produce interference pattern. The observed fringe width is 0.12 mm . The angle between the two wave trains is

A
$5 \times 10^{-1} \mathrm{rad}$
B
$5 \times 10^{-3} \mathrm{rad}$
C
$1 \times 10^{-2} \mathrm{rad}$
D
$1 \times 10^{-3} \mathrm{rad}$
3
MHT CET 2024 15th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A plate of refractive index 1.6 is introduced in the path of light from one of the slits in Young's double slit experiment then

A
the fringe width towards the side of the plate will decrease.
B
the central maximum will shift towards this side
C
number of fringes seen will decrease.
D
interference pattern will disappear.
4
MHT CET 2024 15th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment, the intensity of light at a point on the screen where the path difference is $\lambda$ is x units, $\lambda$ being the wavelength of light used. The intensity at a point where the path difference is $\frac{\lambda}{4}$ will be $\left(\cos 2 \pi=1, \cos \frac{\pi}{2}=0\right)$

A
$\frac{x}{4}$
B
$\frac{x}{2}$
C
$x$
D
zero
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