1
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two beams of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the beams is $$\pi / 2$$ at point $$\mathrm{A}$$ and $$\pi$$ at point $$\mathrm{B}$$. Then the difference between the resultant intensities at $$\mathrm{A}$$ and $$\mathrm{B}$$ is

A
4I
B
5I
C
2I
D
3I
2
MHT CET 2021 23rd September Evening Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment, the intensity at a point where path difference is $$\frac{\lambda}{6}$$ ($$\lambda$$ being the wavelength of light used) is $$I^{\prime}$$. If '$$I_0$$' denotes the maximum intensity, then $$\frac{I}{I_0}$$ is equal to $$\left(\cos 0^{\circ}=1, \cos 60^{\circ}=\frac{1}{\lambda}\right)$$

A
$$\frac{\sqrt{3}}{2}$$
B
$$\frac{4}{3}$$
C
$$\frac{1}{\sqrt{2}}$$
D
$$\frac{1}{2}$$
3
MHT CET 2021 23rd September Evening Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment, the distance of $$\mathrm{n}^{\text {th }}$$ dark band from the central bright band in terms of bandwidth '$$\beta$$' is

A
$$\mathrm{n} \beta$$
B
$$(\mathrm{n}-1) \beta$$
C
$$(\mathrm{n}-0.5) \beta$$
D
$$(\mathrm{n}+0.5) \beta$$
4
MHT CET 2021 23rd September Evening Shift
MCQ (Single Correct Answer)
+1
-0

In biprism experiment, $$6^{\text {th }}$$ bright band with wavelength '$$\lambda_1$$' coincides with $$7^{\text {th }}$$ dark band with wavelength '$$\lambda_2$$' then the ratio $$\lambda_1: \lambda_2$$ is (other setting remains the same)

A
$$7: 6$$
B
$$13: 12$$
C
$$12: 13$$
D
$$6: 7$$
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