MHT CET 2019 2nd May Evening Shift | Rotational Motion Question 98 | Physics

Three point masses each of mass ' $m$ ' are kept at the corners of an equilateral triangle of side. The system rotates about the center of the triangle without any change in the separation of masses during rotation. The period of rotation is directly proportional to $\left(\cos 30^{\circ}=\sin 60^{\circ}=\frac{\sqrt{3}}{2}\right)$

$\sqrt{L}$

$L^{3 / 2}$

$L$

$L^{-2}$

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

When a 12000 joule of work is done on a flywheel, its frequency of rotation increases from 10 Hz to 20 Hz . The moment of inertia of flywheel about its axis of rotation is $\left(\pi^2=10\right)$

$1 \mathrm{~kgm}^2$

$2 \mathrm{~kgm}^2$

$1.688 \mathrm{~kgm}^2$

$1.5 \mathrm{~kgm}^2$

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

A rigid body is rotating with angular velocity ' $\omega$ ' about an axis of rotation. Let $v$ ' be the linear velocity of particle which is at perpendicular distance ' $r$ ' from the axis of rotation. Then the relation $v=r \omega$ ' implies that

$\omega$ does not depend on $r$

$\omega \propto \frac{1}{r}$

$\omega \propto r$

$\omega=0$

MHT CET 2019 2nd May Morning Shift

MCQ (Single Correct Answer)

-0

If radius of the solid sphere is doubled by keeping its mass constant, the ratio of their moment of inertia about any of its diameter is

$1: 8$

$2: 5$

$2: 3$

$1: 4$

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