1
MHT CET 2020 19th October Evening Shift
MCQ (Single Correct Answer)
+1
-0

The Brewster's angle for the glass-air interface is $(54.74)^{\circ}$. If a ray of light passing from air to glass strickes at an angle of incidence $45^{\circ}$, then the angle of refraction is

$$\left[\tan (54.74)^{\circ}=\sqrt{2}, \sin 45=\frac{1}{\sqrt{2}}\right]$$

A
$\sin ^{-1}(\sqrt{2})$
B
$\sin ^{-1}(1)$
C
$\sin ^{-1}(05)$
D
$\sin ^{-1}\left(\frac{1}{\sqrt{2}}\right)$
2
MHT CET 2020 16th October Evening Shift
MCQ (Single Correct Answer)
+1
-0

A light wave of wavelength $$\lambda$$ is incident on a slit of width $$d$$. The resulting diffraction pattern is observed on a screen at a distance $$D$$. If linear width of the principal maxima is equal to the width of the slit, then the distance $$D$$ is

A
$$\frac{2 \lambda}{d}$$
B
$$\frac{d^2}{2 \lambda}$$
C
$$\frac{2 \lambda^2}{d}$$
D
$$\frac{d}{\lambda}$$
3
MHT CET 2020 16th October Evening Shift
MCQ (Single Correct Answer)
+1
-0

When wavelength of light used in optical instruments A and B are 4500$$\mathop A\limits^o $$ and 6000$$\mathop A\limits^o $$ respectively, the ratio of resolving power of A to B will be

A
9 : 16
B
16 : 9
C
7 : 1
D
4 : 3
4
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+1
-0

In diffraction experiment, from a single slit, the angular width of the central maxima does not depend upon

A
ratio of wavelength and slit width
B
distance of the slit from the screen
C
wavelength of light used
D
width of the slit
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