MHT CET 2025 21st April Evening Shift | Rotational Motion Question 8 | Physics

Moment of inertia of a thin uniform rod rotating about the perpendicular axis passing through its centre is ' $I$ '. If the same rod is bent in the form of ring, its moment of inertia about the diameter is ' $\mathrm{I}_1$ '. If $\mathrm{I}_1=\mathrm{xI}$, then the value of ' x ' is

$\frac{2 \pi^2}{3}$

$\frac{3}{2 \pi^2}$

$\frac{3 \pi^2}{4}$

$\frac{4}{3 \pi^2}$

MHT CET 2025 21st April Morning Shift

MCQ (Single Correct Answer)

-0

A disc of mass 25 kg and radius 0.2 m is rotating at 240 r.p.m. A retarding torque brings it to rest in 20 second. If the torque is due to a force applied tangentially on the rim of the disc then the magnitude of the force is

$\frac{\pi}{2} \mathrm{~N}$

$2 \pi \mathrm{~N}$

$\pi \mathrm{N}$

$\quad 4 \pi \mathrm{~N}$

MHT CET 2025 21st April Morning Shift

MCQ (Single Correct Answer)

-0

Two circular loops P and Q of radii ' r ' and ' nr ' are made respectively from a uniform wire. Moment of inertia of loop Q about its axis is 4 times that of loop $P$ about its axis. The value of $n$ is

$(2)^{-2 / 3}$

$(2)^{2 / 3}$

$\sqrt{2}$

$2^{1 / 3}$

MHT CET 2025 21st April Morning Shift

MCQ (Single Correct Answer)

-0

Three spheres, each of mass ' $m$ ' and radius ' $r$ ' are placed as shown in figure. Consider an axis $\mathrm{YY}^{\prime}$, which is touching two spheres and passing through the diameter of third sphere. The moment of inertia of the system consisting of these three spheres about $\mathrm{YY}^{\prime}$ axis is

MHT CET 2025 21st April Morning Shift Physics - Rotational Motion Question 9 English

$\frac{7}{5} \mathrm{mr}^2$

$\frac{2}{5} \mathrm{mr}^2$

$\frac{16}{5} \mathrm{mr}^2$

$\frac{\mathrm{mr}^2}{2}$

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