MHT CET 2021 20th September Morning Shift | Wave Optics Question 51 | Physics

Light of wavelength '$$\lambda$$' is incident on a single slit of width 'a' and the distance between slit and screen is 'D'. In diffraction pattern, if slit width is equal to the width of the central maximum then $$\mathrm{D}=$$

$$\frac{a^2}{\lambda}$$

$$\frac{\mathrm{a}}{\lambda}$$

$$\frac{a^2}{2 \lambda}$$

$$\frac{\mathrm{a}}{2 \lambda}$$

MHT CET 2021 20th September Morning Shift

MCQ (Single Correct Answer)

-0

In Fraunhofer diffraction pattern, slit width is 0.2 mm and screen is at 2m away from the lens. If wavelength of light used is 5000$$\mathop A\limits^o $$ then the distance between the first minimum on either side of the central maximum is ($$\theta$$ is small and measured in radian)

2 $$\times$$ 10$$^{-2}$$ m

10$$^{-1}$$ m

10$$^{-2}$$ m

10$$^{-3}$$ m

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

In diffraction experiment, from a single slit, the angular width of the central maxima does not depend upon

ratio of wavelength and slit width

distance of the slit from the screen

wavelength of light used

width of the slit

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

In Young's double slit experiment green light is incident on the two slits. The interference pattern is observed on a screen. Which one of the following changes would cause the observed fringes to be more closely spaced?

Moving the screen away from the slits

Using blue light instead of green light

Using red light instead of green light

Reducing the separation between the slits

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