1
MHT CET 2021 23th September Morning Shift
+1
-0

In biprims experiment, the $$4^{\text {th }}$$ dark band is formed opposite to one of the slits. The wavelength of light used is $$(\mathrm{d}=$$ distance between the slits, $$\mathrm{D}=$$ distance between scource and the screen)

A
$$\frac{\mathrm{d}^2}{14 \mathrm{D}}$$
B
$$\mathrm{\frac{d^2}{7 D}}$$
C
$$\frac{d^2}{9 \mathrm{D}}$$
D
$$\frac{d^2}{11 \mathrm{D}}$$
2
MHT CET 2021 22th September Evening Shift
+1
-0

In Young's double slit experiment using monochromatic light of wavelength '$$\lambda$$', the maximum intensity of light at a point on the screen is $$\mathrm{K}$$ units. The intensity of light at point where the path difference is $$\frac{\lambda}{3}$$ is

$$\left[\cos 60^{\circ}=\sin 30^{\circ}=\frac{1}{2}\right]$$

A
$$\frac{K}{4}$$
B
$$\frac{3 K}{4}$$
C
K
D
$$\frac{\mathrm{K}}{2}$$
3
MHT CET 2021 22th September Evening Shift
+1
-0

If two sources emit light waves of different amplitudes then

A
brightness of fringes is less.
B
fringes disappear after short time.
C
fringe width is less.
D
there is some intensity of light in the region of destructive interference.
4
MHT CET 2021 22th September Morning Shift
+1
-0

In Young's double slit experiment, the $$10^{\text {th }}$$ maximum of wavelength '$$\lambda_1$$' is at a distance of '$$Y_1$$' from the central maximum. When the wavelength of the source is changed to '$$\lambda_2$$', $$5^{th}$$ maximum is at a distance '$$Y_2$$' from the central maximum. The ratio $$\frac{Y_1}{Y_2}$$ is

A
$$\frac{2 \lambda_1}{\lambda_2}$$
B
$$\frac{\lambda_2}{2 \lambda_1}$$
C
$$\frac{2 \lambda_2}{\lambda_1}$$
D
$$\frac{\lambda_1}{2 \lambda_2}$$
EXAM MAP
Medical
NEET