MHT CET 2025 19th April Evening Shift | Alternating Current Question 8 | Physics

In an $L-R$ circuit, the inductive reactance is equal to $\sqrt{3}$ times the resistance ' $R$ ' of the circuit. An e.1n.f. $\mathrm{E}=\mathrm{E}_0 \sin (\omega \mathrm{t})$ is applied to the circuit. The power consumed in the circuit is

$\frac{\mathrm{E}_0^2}{4 \mathrm{R}}$

$\frac{E_0^2}{6 R}$

$\frac{\mathrm{E}_0^2}{8 \mathrm{R}}$

$\frac{E_0^2}{12 R}$

MHT CET 2025 19th April Evening Shift

MCQ (Single Correct Answer)

-0

An a.c. source is applied to a series LR circuit with $\mathrm{X}_{\mathrm{L}}=3 \mathrm{R}$ and power factor is $\mathrm{X}_1$. Now a capacitor with $\mathrm{X}_{\mathrm{c}}=\mathrm{R}$ is added in series to LR circuit and the power factor is $\mathrm{X}_2$. The ratio $\mathrm{X}_1$ to $\mathrm{X}_2$ is

$1: 2$

$2: 1$

$1: \sqrt{2}$

$\sqrt{2}: 1$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

A series LCR circuit is connected to an a.c. source of $230 \mathrm{~V}, 50 \mathrm{~Hz}$. The circuit contains resistance of $80 \Omega$ an inductor having inductive reactance $70 \Omega$ and a capacitor of capacitive reactance $130 \Omega$. The power factor of the circuit is $x$. The value of $x$ is

0.4

0.8

0.6

0.9

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

An alternating voltage $\mathrm{E}=100 \sqrt{2} \sin (50 \mathrm{t})$ is connected to a $2 \mu \mathrm{~F}$ capacitor through an a.c. ammeter. The ammeter reading will be

10 mA

5 mA

20 mA

30 mA

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