MHT CET 2024 16th May Evening Shift | Alternating Current Question 2 | Physics

In an $L C R$ circuit, if ' $V$ ' is the effective value of the applied voltage, $V_R$ is the voltage across ' $R$ ', ' $\mathrm{V}_{\mathrm{L}}$ ' and ' $\mathrm{V}_{\mathrm{C}}$ ' is the effective voltage across ' L ' and ' $C$ ' respectively then

$\mathrm{V}=\mathrm{V}_{\mathrm{R}}+\mathrm{V}_{\mathrm{L}}+\mathrm{V}_{\mathrm{C}}$

$\mathrm{V}^2=\mathrm{V}_{\mathrm{R}}^2+\mathrm{V}_{\mathrm{L}}^2+\mathrm{V}_{\mathrm{C}}^2$

$\mathrm{V}^2=\mathrm{V}_{\mathrm{R}}^2+\left(\mathrm{V}_{\mathrm{L}}-\mathrm{V}_{\mathrm{c}}\right)^2$

$\mathrm{V}^2=\mathrm{V}_{\mathrm{L}}^2+\left(\mathrm{V}_{\mathrm{R}}-\mathrm{V}_{\mathrm{C}}\right)^2$

MHT CET 2024 16th May Evening Shift

MCQ (Single Correct Answer)

-0

A light bulb connected in series with a capacitor and an a.c. source is glowing with a certain brightness. On reducing the capacity of capacitance and frequency of source, the brightness of the lamp (respectively)

is reduced, is increased

is reduced, is reduced

is increased, is reduced

is increased, is increased

MHT CET 2024 16th May Evening Shift

MCQ (Single Correct Answer)

-0

If a transformer of an audio amplifier has output impedance $8000 \Omega$ and the speaker has input impedance $8 \Omega$, the primary and secondary turns of this transformer connected between the output of amplifier and to loudspeaker should have the ratio

$1000: 1$

$100: 1$

$1: 32$

$32: 1$

MHT CET 2024 16th May Morning Shift

MCQ (Single Correct Answer)

-0

In LCR series circuit, an alternating e.m.f. 'e' and current ' $i$ ' are given by equations $\mathrm{e}=160 \sin (100 \mathrm{t})$ Volt and $\mathrm{i}=250 \sin \left(100 \mathrm{t}+\frac{\pi}{3}\right) \mathrm{mA}$. The average power dissipated in the circuit is

2.5 W

4.0 W

10 W

100 W

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