MHT CET 2023 10th May Morning Shift | Alternating Current Question 85 | Physics

In a series LR circuit, $$X_L=R$$, power factor is $$P_1$$. If a capacitor of capacitance $$C$$ with $$X_C=X_L$$ is added to the circuit the power factor becomes $$P_2$$. The ratio of $$P_1$$ to $$P_2$$ will be

$$1: 3$$

$$1: \sqrt{2}$$

$$1: 1$$

$$1: 2$$

MHT CET 2023 9th May Evening Shift

MCQ (Single Correct Answer)

-0

An e.m.f. $$E=4 \cos (1000 t)$$ volt is applied to an LR circuit of inductance $$3 \mathrm{~mH}$$ and resistance $$4 ~\Omega$$. The maximum current in the circuit is

$$\frac{4}{\sqrt{7}} \mathrm{~A}$$

$$1.0 \mathrm{~A}$$

$$\frac{4}{7} \mathrm{~A}$$

$$0.8 \mathrm{~A}$$

MHT CET 2023 9th May Evening Shift

MCQ (Single Correct Answer)

-0

An alternating voltage of frequency '$$\omega$$' is induced in electric circuit consisting of an inductance '$$L$$' and capacitance '$$C$$', connected in parallel. Then across the inductance coil

current is maximum when $$\omega^2=\frac{1}{\mathrm{LC}}$$

current is zero

voltage is minimum when $$\omega^2=\frac{1}{\text { LC }}$$

voltage is maximum when $$\omega^2=\frac{1}{\mathrm{LC}}$$

MHT CET 2023 9th May Evening Shift

MCQ (Single Correct Answer)

-0

The reactance of capacitor at $$50 \mathrm{~Hz}$$ is $$5 \Omega$$. If the frequency is increased to $$100 \mathrm{~Hz}$$, the new reactance is

$$5 \Omega$$

$$10 \Omega$$

$$2.5 \Omega$$

$$125 \Omega$$

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