In a potentiometer experiement, when three cells $$\mathrm{A}, \mathrm{B}$$ and $$\mathrm{C}$$ are connected in series, the balancing length is found to be $$420 \mathrm{~cm}$$. If cells $$\mathrm{A}$$ and $$\mathrm{B}$$ are connected in series the balancing length is $$220 \mathrm{~cm}$$ and for cells $$\mathrm{B}$$ and $$\mathrm{C}$$ connected in series in balancing length is $$320 \mathrm{~cm}$$. The emf of cells $$\mathrm{A}, \mathrm{B}$$ and $$\mathrm{C}$$ are respectively in the ratio of
To determine the internal resistance of a cell by using a potentiometer, the null point is at $$1 \mathrm{~m}$$ when shunted by $$3 \Omega$$ resistance and at a length $$1.5 \mathrm{~m}$$, when cell is shunted by $$6 \Omega$$ resistance The internal resistance of the cell is
In the given circuit, the current in 8$$\Omega$$ resistance is 1.5 A. The total current (I) flowing in the circuit is
A balanced bridge is shown in the circuit diagram. The metre bridge wire has resistance $$1 \Omega \mathrm{m}^{-1}$$. The current drawn from the battery is (Internal resistance of battery is negligible)
