MHT CET 2019 3rd May Morning Shift | Current Electricity Question 57 | Physics

A potentiometer wire has length $L$ For given cell of emf $E$, the balancing length is $\frac{L}{3}$ from the positive end of the wire. If the length of potentiometer wire is increased by $50 \%$, then for the same cell, the balance point is obtained at length

$\frac{L}{2}$ from positive end

$\frac{L}{5}$ from positive end

$\frac{L}{3}$ from positive end

$\frac{L}{4}$ from positive end

MHT CET 2019 3rd May Morning Shift

MCQ (Single Correct Answer)

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In the network shown cell E has internal resistance $r$ and the galvanometer shows zero deflection. If the cell is replaced by a new cell of emf $2 E$ and internal resistance $3 r$ keeping everything else identical, then

MHT CET 2019 3rd May Morning Shift Physics - Current Electricity Question 2 English

The galvanometer will show deflection of 10 divisions.

The galvanometer show zero deflection,

Current will flow from $B$ to $A$.

Current will flow from $A$ to $B$.

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

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The range of an ammeter of resistance ' $G$ can be increased from ' $I$ ' to ' $nI$ ' by connecting

a series resistance of $\frac{G}{n+1} \Omega$

a shunt of $\frac{G}{n-1} \Omega$

a shunt of $\frac{G}{n+1} \Omega$

a series resistance of $\frac{G}{n-1} \Omega$

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

In the given electrical circuit, which one of the following equations is a correct equation?

$E_2-i_2 r_2-E_1-i_1 r_1=0$

$E_1-\left(i_1+i_2\right) R+i_1 r_1=0$

$E_1-\left(i_1+i_2\right) R-i_1 r_1=0$

$-E_2-\left(i_1+i_2\right) R+i_2 r_2=0$

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