1
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In an ammeter, $4 \%$ of the main current is passing through the galvanometer, If shunt resistance is $5 \Omega$, then resistance of galvanometer will be

A
$60 \Omega$
B
$120 \Omega$
C
$240 \Omega$
D
$480 \Omega$
2
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

When the two known resistance ' $R$ ' and ' $S$ ' are connected in the left and right gaps of a meter bridge respectively, the null point is found at a distance ' $l_1$ ' from the zero end of a meter bridge wire. An unknown resistance ' X ' is now connected in parallel with ' S ' and null point is found at a distance ' $l_2$ ' form zero end of meter bridge wire. The unknown resistance ' X ' is

A
$\frac{\mathrm{S} l_1\left(100-l_2\right)}{100\left(l_2-l_1\right)}$
B
$\frac{\mathrm{S} l_2\left(100-l_1\right)}{100\left(l_1-l_2\right)}$
C
$\frac{100\left(l_2-l_1\right)}{\mathrm{Sl}_1\left(100-l_2\right)}$
D
$\frac{100\left(l_2-l_1\right)}{\mathrm{S} l_2\left(100-l_1\right)}$
3
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a Wheatstone's bridge, the resistances in four arms are as shown in the figure. The balancing condition of the bridge is

MHT CET 2024 4th May Evening Shift Physics - Current Electricity Question 31 English

A
$\frac{\mathrm{P}}{\mathrm{Q}}=\frac{\mathrm{R}}{\mathrm{S}_1+\mathrm{S}_2}$
B
$\frac{P}{Q}=\frac{R\left(S_1 S_2\right)}{S_1+S_2}$
C
$\frac{P}{Q}=\frac{R\left(S_1+S_2\right)}{2 S_1 S_2}$
D
$\frac{\mathrm{P}}{\mathrm{Q}}=\frac{\mathrm{R}\left(\mathrm{S}_1+\mathrm{S}_2\right)}{\mathrm{S}_1 \mathrm{~S}_2}$
4
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

When a galvanometer is shunted by a resistance ' $s$ ', its current capacity increases ' $n$ ' times. If the same galvanometer is shunted by another resistance ' $s_1$ ', its capacity will increase to ' $n_1$ ' times original current. The value of ' $n_1$ ' is

A
$\frac{(\mathrm{n}+\mathrm{s})}{\mathrm{s}_1}$
B
$\frac{s_1(n-s)-s_1}{s_1}$
C
$\frac{(n+1) s}{s_1}$
D
$\frac{\mathrm{s}(\mathrm{n}-1)+\mathrm{s}_1}{\mathrm{~s}_1}$
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