MHT CET 2024 10th May Evening Shift | Alternating Current Question 24 | Physics

For the series $L C R$ circuit, $R=\frac{X_L}{2}=2 \mathrm{X}_{\mathrm{c}}$. The impedance of the circuit and the phase difference between V and I will be

$\frac{\sqrt{5}}{2} \mathrm{R}, \tan ^{-1}\left(\frac{1}{2}\right)$

$\frac{\sqrt{13}}{2} R, \tan ^{-1}\left(\frac{3}{2}\right)$

$\sqrt{5} R, \tan ^{-1}(1)$

$\sqrt{13} \mathrm{R}, \tan ^{-1}(2)$

MHT CET 2024 10th May Morning Shift

MCQ (Single Correct Answer)

-0

An e.m.f. $E=E_0 \cos \omega t$ is applied to the $L-R$ circuit. The inductive reactance is equal to the resistance ' $R$ ' of the circuit. The power consumed in the circuit is

$\frac{E_0^2}{\sqrt{2} R}$

$\frac{E_0^2}{2 R}$

$\frac{E_0^2}{4 R}$

$\frac{E_0^2}{R}$

MHT CET 2024 10th May Morning Shift

MCQ (Single Correct Answer)

-0

A series resonant circuit consists of inductor ' $L$ ' of negligible resistance and a capacitor ' $C$ ' which produces resonant frequency ' $f$ '. If $L$ is changed to 3 L and ' C ' is changed to 6 C , the resonant frequency will become.

$\frac{\mathrm{f}}{6}$

$\frac{\mathrm{f}}{3}$

$\frac{\mathrm{f}}{2 \sqrt{2}}$

$\frac{\mathrm{f}}{3 \sqrt{2}}$

MHT CET 2024 10th May Morning Shift

MCQ (Single Correct Answer)

-0

The inductive reactance of a coil is ' $R$ ' $\Omega$. If inductance of a coil is tripled and frequency of a.c supply is also tripled, then new inductive reactance will be

$\frac{\mathrm{R}}{9}$

$\frac{\mathrm{R}}{3}$

$\mathrm{3 R}$

$\mathrm{9 R}$

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