MHT CET 2019 3rd May Morning Shift | Rotational Motion Question 96 | Physics

A solid sphere rolls down from top of inclined plane, 7 m high, without slipping. Its linear speed at the foot of plane is $\left(g=10 \mathrm{~m} / \mathrm{s}^2\right)$

$\sqrt{70} \mathrm{~m} / \mathrm{s}$

$\sqrt{\frac{140}{3}} \mathrm{~m} / \mathrm{s}$

$\sqrt{\frac{280}{3}} \mathrm{~m} / \mathrm{s}$

$\sqrt{100} \mathrm{~m} / \mathrm{s}$

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

Three identical rods each of mass ' $M$ ' and length ' $L$ ' are joined to form a symbol ' $H$. The moment of inertia of the system about one of the sides of ' $H$ ' is

$\frac{2 M L^2}{3}$

$\frac{M L^2}{2}$

$\frac{M L^2}{6}$

$\frac{4 M L^2}{3}$

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

Three point masses each of mass ' $m$ ' are kept at the corners of an equilateral triangle of side. The system rotates about the center of the triangle without any change in the separation of masses during rotation. The period of rotation is directly proportional to $\left(\cos 30^{\circ}=\sin 60^{\circ}=\frac{\sqrt{3}}{2}\right)$

$\sqrt{L}$

$L^{3 / 2}$

$L$

$L^{-2}$

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

When a 12000 joule of work is done on a flywheel, its frequency of rotation increases from 10 Hz to 20 Hz . The moment of inertia of flywheel about its axis of rotation is $\left(\pi^2=10\right)$

$1 \mathrm{~kgm}^2$

$2 \mathrm{~kgm}^2$

$1.688 \mathrm{~kgm}^2$

$1.5 \mathrm{~kgm}^2$

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