1
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A single slit of width $d$ is illuminated by violet light of wavelength 400 nm and the width of the diffraction pattern is measured as ' Y '. When half of the slit width is covered and illuminated by yellow light of wavelength 600 nm , the width of the diffraction pattern is

A
zero
B
$\frac{Y}{3}$
C
3 Y
D
4 Y
2
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a biprism experiment, monochromatic light of wavelength ' $\gamma$ ' is used. The distance between the two coherent sources ' $d$ ' is kept constant. If the distance between slit and eyepiece ' $D$ ' is varied as $D_1, D_2, D_3, D_4$ and corresponding measured fringe widths are $\mathrm{W}_1, \mathrm{~W}_2, \mathrm{~W}_3, \mathrm{~W}_4$ then

A
$\mathrm{W}_1 \mathrm{D}_1=\mathrm{W}_2 \mathrm{D}_2=\mathrm{W}_3 \mathrm{D}_3=\mathrm{W}_4 \mathrm{D}_4$
B
$\frac{\mathrm{W}_1}{\mathrm{D}_1}=\frac{\mathrm{W}_2}{\mathrm{D}_2}=\frac{\mathrm{W}_3}{\mathrm{D}_3}=\frac{\mathrm{W}_4}{\mathrm{D}_4}$
C
$\mathrm{W}_1 \sqrt{\mathrm{D}_1}=\mathrm{W}_2 \sqrt{\mathrm{D}_2}=\mathrm{W}_3 \sqrt{\mathrm{D}_3}=\mathrm{W}_3 \sqrt{\mathrm{D}_3}$
D
$\mathrm{D}_1 \sqrt{\mathrm{~W}_1}=\mathrm{D}_2 \sqrt{\mathrm{~W}_2}=\mathrm{D}_3 \sqrt{\mathrm{~W}_3}=\mathrm{D}_4 \sqrt{\mathrm{~W}_4}$
3
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Three identical polaroids $P_1, P_2$ and $P_3$ are placed one after another. The pass axis of $P_2$ and $P_3$ are inclined at an angle $60^{\circ}$ and $90^{\circ}$ with respect to axis of $P_1$. The source has an intensity $I_0$. The intensity of transmitted light through $P_3$ is $\left(\cos 60^{\circ}=0.5, \cos 30^{\circ}=\frac{\sqrt{3}}{2}\right)$

A
$\frac{\mathrm{I}_0}{8}$
B
$\frac{3 \mathrm{I}_0}{16}$
C
$\frac{3 \mathrm{I}_0}{32}$
D
$\frac{\mathrm{I}_0}{32}$
4
MHT CET 2024 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment, in an interference pattern, second minimum is observed exactly in front of one slit. The distance between the two coherent sources is ' $d$ ' and the distance between the source and screen is ' $D$ '. The wave length of light $(\lambda)$ used is

A
$\frac{\mathrm{d}^2}{\mathrm{D}}$
B
$\frac{\mathrm{d}^2}{2 \mathrm{D}}$
C
$\frac{\mathrm{d}^2}{3 \mathrm{D}}$
D
$\frac{d^2}{4 D}$
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