MHT CET 2025 26th April Evening Shift | Rotational Motion Question 5 | Physics

A man standing on a turn-table is rotating at a certain angular frequency with his arms outstretched. He suddenly folds his arms. If his moment of inertia with folded arms is $75 \%$ of that with outstretched arms, then his rotational kinetic energy will

increase by $33.3 \%$

decrease by $33.3 \%$

increase by $25.0 \%$

decrease by $25.0 \%$

MHT CET 2025 26th April Morning Shift

MCQ (Single Correct Answer)

-0

A rigid body rotates about a fixed axis with variable angular velocity $(\alpha-\beta t)$ at time $t$, where $\alpha$ and $\beta$ are constants. The angle through which it rotates before it comes to rest is

$\frac{\alpha}{\beta}$

$\frac{\alpha^2}{\beta}$

$\frac{\alpha^2}{2 \beta}$

$\frac{\alpha}{2 \beta}$

MHT CET 2025 26th April Morning Shift

MCQ (Single Correct Answer)

-0

Moment of inertia of a solid sphere about its diameter is 'I'. It is then casted into 27 small spheres of same diameter. The moment of inertia of each small sphere about its diameter is

$\frac{1}{44}$

$\frac{\mathrm{I}}{188}$

$\frac{1}{204}$

$\frac{1}{243}$

MHT CET 2025 26th April Morning Shift

MCQ (Single Correct Answer)

-0

Moment of inertia of the rod about an axis passing through the centre and perpendicular to its length is ' $I_1$ '. The same rod is bent into a ring and its moment of inertia about the diameter is ' $I_2$ '. Then $I_1 / I_2$ is

$\frac{3 \pi^2}{2}$

$\frac{2 \pi^2}{3}$

$\frac{\pi^2}{3}$

$\frac{\pi^2}{9}$

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