MHT CET 2025 19th April Evening Shift | Electrostatics Question 9 | Physics

A charged particle of mass ' $m$ ' and charge ' $q$ ' is at rest. It is acce:lerated in a uniform electric field of intensity ' $E$ ' : for time ' $t$ '. The kinetic energy of the particles after time $t$ is

$\frac{E q m}{2 t}$

$\frac{E^2 q^2 t^2}{2 m}$

$\frac{2 \mathrm{E}^2 \mathrm{t}^2}{\mathrm{mq}^2}$

$\frac{\mathrm{Eqt}}{\mathrm{m}}$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

Let ' $W$ ' joule be the work done to move an electric charge ' $q$ ' coulomb from a place $A$, where potential is -5 volt to another place $B$ where potential is ' $V$ ' volt. The value of ' $V$ ' is

$W q-5$

$\frac{\mathrm{q}}{\mathrm{w}}+5$

$W-\frac{5}{q}$

$\frac{w}{q}-5$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

Two charges $\mathrm{q}_1=+6_{\mathrm{q}}$ and $\mathrm{q}_2=-3 \mathrm{q}$ placed as shown in figure. A proton is placed on x -axis away from $\mathrm{q}_2$. To remain proton in equilibrium, the distance between $\mathrm{q}_1$ and proton is

MHT CET 2025 19th April Morning Shift Physics - Electrostatics Question 7 English

$\left(\frac{\sqrt{2}}{\sqrt{2}-1}\right) \mathrm{L}$

$\mathrm{2 L}$

$\frac{\mathrm{L}}{2}$

$\left(\frac{\sqrt{2}}{\sqrt{2}+1}\right) \mathrm{L}$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

An electric dipole of dipole moment ' $p$ ' is aligned parallel to a uniform electric field ' E '. The energy required to rotate the dipole by $90^{\circ}$ is $\left[\begin{array}{ll}\sin 0^{\circ}=0, & \sin 90^{\circ}=1 \\ \cos 0^{\circ}=1, & \cos 90^{\circ}=0\end{array}\right]$

$pE$

$\mathrm{pE}^2$

$p^2 E$

infinity

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