MHT CET 2023 14th May Evening Shift | Electrostatics Question 45 | Physics

A charge $$17.7 \times 10^{-4} \mathrm{C}$$ is distributed uniformly over a large sheet of area $$200 \mathrm{~m}^2$$. The electric field intensity at a distance $$20 \mathrm{~cm}$$ from it in air will be $$\left[\varepsilon_0=8.85 \times 10^{-12} \mathrm{C}^2 / \mathrm{Nm}^2\right]$$

$$5 \times 10^5 \mathrm{~N} / \mathrm{C}$$

$$6 \times 10^5 \mathrm{~N} / \mathrm{C}$$

$$7 \times 10^5 \mathrm{~N} / \mathrm{C}$$

$$8 \times 10^5 \mathrm{~N} / \mathrm{C}$$

MHT CET 2023 14th May Evening Shift

MCQ (Single Correct Answer)

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If $$\mathrm{E}_{\mathrm{a}}$$ and $$\mathrm{E}_{\mathrm{q}}$$ represent the electric field intensity due to a short dipole at a point on its axial line and on the equatorial line at the same distance '$$r$$' from the centre of the dipole, then

$$\mathrm{E}_{\mathrm{a}}=\mathrm{E}_{\mathrm{q}}$$

$$\mathrm{E}_{\mathrm{a}}=\frac{1}{2} \mathrm{E}_{\mathrm{q}}$$

$$\mathrm{E}_{\mathrm{a}}=\frac{1}{\sqrt{2}} \mathrm{E}_{\mathrm{q}}$$

$$\mathrm{E}_{\mathrm{a}}=2 \mathrm{E}_{\mathrm{q}}$$

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

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The electric field intensity on the surface of a solid charged sphere of radius '$$r$$' and volume charge density '$$\rho$$' is ($$\varepsilon_0=$$ permittivity of free space)

$$\frac{\rho r}{3 \varepsilon_0}$$

$$\frac{\rho}{4 \pi \varepsilon_0 \mathrm{r}}$$

zero

$$\frac{5 \rho \mathrm{r}}{6 \varepsilon_0}$$

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

-0

A uniformly charged semicircular arc of radius '$$r$$' has linear charge density '$$\lambda$$'. The electric field at its centre is ( $$\varepsilon_0=$$ permittivity of free space)

$$\frac{\lambda}{4 \varepsilon_0}$$

$$\frac{2 \varepsilon_0}{\lambda}$$

$$\frac{\lambda}{4 \varepsilon_0 \mathrm{r}}$$

$$\frac{2 \pi \varepsilon_0}{\lambda}$$

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